Task
Given a string, SS, of length NN that is indexed from 00 to N−1N−1, print its even-indexed and odd-indexed characters as 22 space-separated strings on a single line (see the Sample below for more detail).

Note: 00 is considered to be an even index.

Input Format

The first line contains an integer, TT (the number of test cases).
Each line ii of the TT subsequent lines contain a String, SS.

Constraints

Output Format

For each String SjSj (where 0≤j≤T−10≤j≤T−1), print SjSj‘s even-indexed characters, followed by a space, followed by SjSj‘s odd-indexed characters.

Sample Input

2

Hacker

Rank

Sample Output

Hce akr

Rn ak

Explanation

Test Case 0: S=“Hacker”
S[0]=“H”
S[1]=“a”
S[2]=“c”
S[3]=“k”
S[4]=“e”
S[5]=“r”
The even indices are 0, 2, and 4, and the odd indices are 1, 3, and 5. We then print a single line of 2 space-separated strings; the first string contains the ordered characters from S‘s even indices (Hce), and the second string contains the ordered characters from S‘s odd indices (akr).

Test Case 1: S=“Rank”
S[0]=“R”
S[1]=“a”
S[2]=“n”
S[3]=“k”
The even indices are 0 and 2, and the odd indices are 1 and 3. We then print a single line of 2 space-separated strings; the first string contains the ordered characters from S‘s even indices (Rn), and the second string contains the ordered characters from S‘s odd indices (ak).

C program:

#include <stdio.h>

#include <stdlib.h>

int main() {

   int t;

    scanf("%d",&t);

    while(t)

        {

        char a[10000];

        scanf("%s",a);

        int i=0;

        while(a[i]!='\0')

        {if(i%2==0)

            printf("%c",a[i]);

        i++;}

       i=0;

        printf(" ");

        while(a[i]!='\0')

        {if(i%2!=0)

            printf("%c",a[i]);

        i++;}

        t--;

        printf("\n");

    }

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */   

    return 0;

}

Task
Given an integer, , print its first  multiples. Each multiple  (where ) should be printed on a new line in the form: n x i = result.

Input Format

A single integer, .

Constraints

Output Format

Print 10 lines of output; each line  (where 1<=i<=10) contains the n x i of  in the form:
n x i = result.

Sample Input

2

Sample Output

2 x 1 = 2

2 x 2 = 4

2 x 3 = 6

2 x 4 = 8

2 x 5 = 10

2 x 6 = 12

2 x 7 = 14

2 x 8 = 16

2 x 9 = 18

2 x 10 = 20

C code:

#include <stdio.h>

int main(){

    int N,i; 

    scanf("%d",&N);

    for(i=1;i<=10;i++)

    printf("%d x %d = %d\n",N,i,N*i);

    return 0;

}

Task
Given the meal price (base cost of a meal), tip percent (the percentage of the meal price being added as tip), and tax percent (the percentage of the meal price being added as tax) for a meal, find and print the meal's total cost.

Note: Be sure to use precise values for your calculations, or you may end up with an incorrectly rounded result!

Input Format

There are  lines of numeric input:
The first line has a double,  (the cost of the meal before tax and tip).
The second line has an integer,  (the percentage of  being added as tip).
The third line has an integer,  (the percentage of  being added as tax).

Output Formata

Print The total meal cost is totalCost dollars., where  is the rounded integer result of the entire bill ( with added tax and tip).

Sample Input

12.00

20

8

Sample Output

The total meal cost is 15 dollars.

Explanation

Given:
, , 

Calculations:  

We round  to the nearest dollar (integer) and then print our result:

The total meal cost is 15 dollars.

C Program:

#include <stdio.h>

#include <string.h>

#include <math.h>

#include <stdlib.h>

int main() {

         float mc,tp,tx,tc;

    int tip,tax,l,m;

    scanf("%f\n%d\n%d",&mc,&tip,&tax);

    tp=mc*tip/100;

    tx=mc*tax/100;

    tc=mc+tp+tx;

    l=tc;

    m=(tc*100)-(l*100);

    l=(m>=50)?l+1:l;

    printf("The total meal cost is %d dollars.",l);

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */    

    return 0;

}