Day 5: Loops-hackerrank-solution

                                               Day 5: Loops-hackerrank-solution

Task
Given an integer, , print its first  multiples. Each multiple  (where ) should be printed on a new line in the form: n x i = result.

Input Format

A single integer, .

Constraints

•  2<=n<=20

Output Format

Print 10 lines of output; each line  (where 1<=i<=10) contains the n x i of  in the form:
n x i = result.

Sample Input

2

Sample Output

2 x 1 = 2

2 x 2 = 4

2 x 3 = 6

2 x 4 = 8

2 x 5 = 10

2 x 6 = 12

2 x 7 = 14

2 x 8 = 16

2 x 9 = 18

2 x 10 = 20

C code:

#include <stdio.h>

int main(){

    int N,i; 

    scanf("%d",&N);

    for(i=1;i<=10;i++)

    printf("%d x %d = %d\n",N,i,N*i);

    return 0;

}