Day 6: Let's Review-hackerrank-solution

                                             Day 6: Let's Review-hackerrank-solution

Task
Given a string, SS, of length NN that is indexed from 00 to N−1N−1, print its even-indexed and odd-indexed characters as 22 space-separated strings on a single line (see the Sample below for more detail).

Note: 00 is considered to be an even index.

Input Format

The first line contains an integer, TT (the number of test cases).
Each line ii of the TT subsequent lines contain a String, SS.

Constraints

• 1≤T≤101≤T≤10
• 2≤length of S≤100002≤length of S≤10000

Output Format

For each String SjSj (where 0≤j≤T−10≤j≤T−1), print SjSj‘s even-indexed characters, followed by a space, followed by SjSj‘s odd-indexed characters.

Sample Input

2

Hacker

Rank

Sample Output

Hce akr

Rn ak

Explanation

Test Case 0: S=“Hacker”
S[0]=“H”
S[1]=“a”
S[2]=“c”
S[3]=“k”
S[4]=“e”
S[5]=“r”
The even indices are 0, 2, and 4, and the odd indices are 1, 3, and 5. We then print a single line of 2 space-separated strings; the first string contains the ordered characters from S‘s even indices (Hce), and the second string contains the ordered characters from S‘s odd indices (akr).

Test Case 1: S=“Rank”
S[0]=“R”
S[1]=“a”
S[2]=“n”
S[3]=“k”
The even indices are 0 and 2, and the odd indices are 1 and 3. We then print a single line of 2 space-separated strings; the first string contains the ordered characters from S‘s even indices (Rn), and the second string contains the ordered characters from S‘s odd indices (ak).

C program:

#include <stdio.h>

#include <stdlib.h>

int main() {

   int t;

    scanf("%d",&t);

    while(t)

        {

        char a[10000];

        scanf("%s",a);

        int i=0;

        while(a[i]!='\0')

        {if(i%2==0)

            printf("%c",a[i]);

        i++;}

       i=0;

        printf(" ");

        while(a[i]!='\0')

        {if(i%2!=0)

            printf("%c",a[i]);

        i++;}

        t--;

        printf("\n");

    }

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */   

    return 0;

}