Two numbers A and B are passed as input. The program must print the odd numbers from A to B (inclusive of A and B) interlaced with the even numbers from B to A.

Input Format:
The first line denotes the value of A.
The second line denotes the value of B.

Output Format:
The odd and even numbers interlaced, each separated by a space.

Boundary Conditions:
1 <= A <= 9999999
A <  B <= 9999999

Example Input/Output 1:
Input:
5
11

Output:
5 10 7 8 9 6 11

Explanation:
The odd numbers from 5 to 11 are 5 7 9 11
The even numbers from 11 to 5 (that is in reverse direction) are 10 8 6
So these numbers are interlaced to produce 5 10 7 8 9 6 11

Example Input/Output 2:
Input:
4
14

Output:
14 5 12 7 10 9 8 11 6 13 4

Explanation:
The odd numbers from 4 to 14 are 5 7 9 11 13
The even numbers from 14 to 4 (that is in reverse direction) are 14 12 10 8 6 4
So these numbers are interlaced to produce 14 5 12 7 10 9 8 11 6 13 4
(Here as the even numbers count are more than the odd numbers count we start with the even number in the output)

Example Input/Output 3:
Input:
3
12

Output:
3 12 5 10 7 8 9 6 11 4

Explanation:
The odd numbers from 3 to 12 are 3 5 7 9 11
The even numbers from 12 to 3 (that is in reverse direction) are 12 10 8 6 4
So these numbers are interlaced to produce 3 12 5 10 7 8 9 6 11 4

program:

#include<stdio.h>

#include <stdlib.h>

int main()

{

int a,b;

scanf("%d\n%d",&a,&b);

int o,e;

if(b%2==0)

e=b;

else

e=b-1;

if(a%2==1)

o=a;

else

o=a+1;

int p=0,t=b-a+1;

while(p<t)

{

    if(a%2==0&&b%2==0)

    {

        if(e>=a)

        {

            printf("%d ",e);

            p++;

            e=e-2;

        }

        if(o<=b)

        {

            printf("%d ",o);

            p++;

            o=o+2;

        }

    }

    else

    {

        if(o<=b)

        {

            printf("%d ",o);

            p++;

            o=o+2;

        }

        if(e>=a)

        {

            printf("%d ",e);

            p++;

            e=e-2;

        }

    }

}

}

The program must accept an integer value N and print the corresponding calendar month in words.
1 - January, 2 - February, .... , 11 - November, 12 - December

If any value apart from 1 to 12 is passed as input, the program must print "Invalid Input".

Input Format:
The first line denotes the value of N.

Output Format:
The first line contains the output as per the description. (The output is CASE SENSITIVE).

Boundary Conditions:
1 <= N <= 12

Example Input/Output 1:
Input:
5

Output:
May

Example Input/Output 2:
Input:
12

Output:
December

Example Input/Output 3:
Input:
105

Output:
Invalid Input

program:

#include<stdio.h>

#include <stdlib.h>

int main()

{

int n;

scanf("%d",&n);

    switch(n)

    {

        case 1:

            printf("January");

            break;

        case 2:

            printf("February");

            break;

        case 3:

            printf("March");

            break;

        case 4:

            printf("April");

            break;

        case 5:

            printf("May");

            break;

        case 6:

            printf("June");

            break;

        case 7:

            printf("July");

            break;

        case 8:

            printf("August");

            break;

        case 9:

            printf("September");

            break;

        case 10:

            printf("October");

            break;

        case 11:

            printf("November");

            break;

        case 12:

            printf("December");

            break;

        default:

            printf("Invalid Input");

    }

}

Two string values S1 and S2 are passed as input. The program must print the output as S1 Technologies S2.

Input Format:
The first line denotes the value of S1.
The second line denotes the value of S2.

Output Format:
The first line contains the output as per the description. There must be exactly one space between the words.

Boundary Conditions:
Length of S1 is from 1 to 100.
Length of S2 is from 1 to 100.

Example Input/Output 1:
Input:
Wipro
Bangalore

Output:
Wipro Technologies Bangalore

Example Input/Output 2:
Input:
ABC
Mumbai

Output:
ABC Technologies Mumbai

Program:

print(input()+" Technologies "+input())

Given a positive integer N as the input, the program must print yes if N is a perfect number. Else no must be printed.

Input Format:
The first line contains N.

Output Format:
The first line contains yes or no

Boundary Conditions:
1 <= N <= 999999

Example Input/Output 1:
Input:
6

Output:
yes

Example Input/Output 2:
Input:
8

Output:
no

Program:

#include<stdio.h>

#include <stdlib.h>

int main()

{

int n,s=0;

scanf("%d",&n);

for(int i=1;i<=n/2;i++)

{

    if(n%i==0)

    {

        s=s+i;

    }

}

if(s==n)

{

    printf("yes");

}

else

{

    printf("no");

}

}

Given an integer N as the input, print the pattern as given in the Example Input/Output section.

Input Format:
The first line contains N.

Output Format:
2N-1 lines containing the desired pattern.

Boundary Conditions:
2 <= N <= 50

Example Input/Output 1:
Input:
3

Output:
0 0 1 0 0
0 2 0 8 0
3 0 0 0 7
0 4 0 6 0
0 0 5 0 0

Example Input/Output 2:
Input:
5

Output:
0 0 0 0 1 0 0 0 0
0 0 0 2 0 16 0 0 0
0 0 3 0 0 0 15 0 0
0 4 0 0 0 0 0 14 0
5 0 0 0 0 0 0 0 13
0 6 0 0 0 0 0 12 0
0 0 7 0 0 0 11 0 0
0 0 0 8 0 10 0 0 0
0 0 0 0 9 0 0 0 0

c program:

#include<stdio.h>

#include <stdlib.h>

int main()

{

int n;

scanf("%d",&n);

for(int i=0;i<2*n-1;i++)

{

    for(int j=0;j<2*n-1;j++)

    {

        if(i==n-j-1)

        {

            printf("%d ",i+1);

        }

        else if(i==j-n+1)

        {

            printf("%d ",4*n-i-3);

        }

        else if(i==j+n-1)

        {

            printf("%d ",i+1);

        }

        else if(n-1==i+j+2-2*n)

        {

          printf("%d ",4*n-i-3);  

        }

        else

        {

            printf("0 ");

        }

    }

    printf("\n");

}

}